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Berichten die geplaatst zijn door Azazel
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Hallo satvrienden,
@fluister
Als eerste wil ik je bedanken dat je betreffende deze kwestie meedenkt en een postieve bijdrage probeerd te leveren.
Natuurlijk is nano82 belangrijk, maar het is, zoals jezelf al zegt niet de enige belangrijke data die we zoeken.
Op P6 ziet het als volgt uit:
C1 3C 01 BF 63 10 01 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 81
Status : 90 1D
Bij PZ -> 81 krijg ik een 90 1D.
Ik ga even een stukje terug in de posting en gebruik de nano82 op de positie die werd aangegeven door Kimble. Naar aanleiding daarvan zal ik het hele verhaaltje iets gedetailleerder uitleggen zodat er meerderen hiermee kunnen gaan 'spelen' cq testen. Alle hulp is welkom gezien de hoeveelheid van combinaties. Dit gaat echt dagen...... weken.. in beslag nemen.
Dus ff terug in de tijd:
We gaan nano82 op de positie zetten zoals destijds aangegeven door Kimble:
Ins > c1 3c 01 bf 90
Data > 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 f6
Status < 90 37
Wat we dus gaan doen is de waarde van PZ veranderen totdat we de status 90 1D krijgen. (de waarde vanaf 00 tot FF)
Ins > c1 3c 01 bf 90
Data > 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 C6
Status < 90 1D
Zoals men kan zien verkrijgen we pas de 90 1D totdat we bij PZ->C6 zijn aangekomen.
Maar we gaan verder:
Nu moeten we dezelfde cyclus toepassen op de bytes ervoor, totdat we dus de 90 1D krijgen... (dit is wel heel lang werk, maar het is de moeite waard)
We zullen de bytes voor de Pz, Pz-1, Pz-2, Pz-3, Pz-4, enz. noemen, dus:
C1 3C 01 BF 90 10 01 .....82.....-1 C6
C1 3C 01 BF 90 10 01 .....82.....-2 -1 C6
C1 3C 01 BF 90 10 01 .....82.....-3 -2 -1 C6
Wat we nu gaan doen is de Pz-1, Pz-2 enz., van waardes 00 tot FF voorzien totdat we dus met dezelfde Ins. 90 1D krijgen.
Ook belangrijk om te even uit te leggen is de P2. Nadat we dus de 90 1D hebben verkregen gaan we er even vanuit dat nano82 op de correcte positie staat, daarna sturen we de ins. voor het controleren van de 'gebruikte key' die door Kimble als BF is gezet. Let op deze key is dus niet echt maar verzonnen, en omdat deze key niet op de kaart aanwezig is geeft ie dus vanzelfsprekend dit repsons.
Goed we gaan weer verder met de waardes Pz, Pz-1, Pz-2 enz.
We beginnen dus op Pz-1.
Ins > c1 3c 01 bf 90
Data > 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 01 c6
Status < 90 37
Ins > c1 3c 01 bf 90
Data > 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 02 C6
Status < 90 02
Ins > c1 3c 01 bf 90
Data > 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 03 C6
Status < 90 37
Enz. enz... totdat we bij 99 komen:
Ins > c1 3c 01 bf 90
Data > 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 99 C6
Status < 90 1D
Op naar de volgen.... de Pz-2:
Ins > c1 3c 01 bf 90
Data > 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 01 99 C6
Status < 90 37
Ins > c1 3c 01 bf 90
Data > 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 02 99 C6
Status < 90 37
......................tot de c8 krijgen we dus geen 90 1D.
Ins > c1 3c 01 bf 90
Data > 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 C8 99 C6
Status < 90 1D
Ik ga even een aantal stappen vooruit en kom uit bij:
Ins > c1 3c 01 bf 90
Data > 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 [color:"black"] 35 [/color] FD DB D3 FA CE C0 03 05 00 0B 00 F3 A4 4B 00 D3 37 F5 9B 2D 00 A6 07 E7 C4 6A 53 F7 07 00 C8 99 C6
Status < [color:"black"] 90 1D [/color]
En zo door......
Nu kunnen we de nano82 op verschillende plaatsen gaan plaatsen en dezelfde cyclus gaan volgen......
Saludos!
'Azazel miembro del equipo RAIDEN, la resitencia.'
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Hallo satvrienden,
zoals we kunnen zien begint het nu echt leuk te worden..
Met veel dank aan Novatorx, die vele uren aan testen e.d. verslijt, kunnen we veel nieuwe dingen ontdekken.
Ik blijf zelf ook intensief bezig met testen, testen en nog eens testen en zal jullie op de hoogte houden.
Saludos!
'Azazel miembro del equipo RAIDEN, la resistencia.'
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C1 3C 01 BF 90 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 45 90 1D
C1 3C 01 BF 90 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 A2 90 1D
C1 3C 01 BF 90 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 DC 90 1D
C1 3C 01 BF 90 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 FD 90 1D
C1 3C 01 BF 90 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 80 90 1D
C1 3C 01 BF 90 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 2C 90 1D
C1 3C 01 BF 90 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 F2 90 1D
C1 3C 01 BF 90 3C 10 01 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 3D 90 1D
C1 3C 01 BF 90 3C 10 01 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 4D 90 1D
C1 3C 01 BF 90 3C 10 01 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 DA 90 1D
C1 3C 01 BF 90 3C 10 01 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 BF 90 1D
C1 3C 01 BF 90 3C 10 01 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 0E 90 1D
C1 3C 01 BF 90 3C 10 01 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 85 90 1D
C1 3C 01 BF 90 3C 10 01 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 02 90 1D
C1 3C 01 BF 90 3C 10 01 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 22 90 1D
C1 3C 01 BF 90 3C 10 01 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 A7 90 1D
C1 3C 01 BF 90 3C 10 01 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 C7 90 1D
C1 3C 01 BF 90 3C 10 01 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 DD 90 1D
C1 3C 01 BF 90 10 01 11 22 33 44 55 66 [82] Pz-135 Pz-134 Pz-133...........Pz-1 Pz -> 90 1D; waarbij de bytes tussen P4 en [82] (11 22 33 44 55 66) we geen 90 1D als respons krijgen bij het verplaatsen van [82] in zijn 'posities' en verplaatse van byte 00 in de SSE (rechts van de [82]) om de LEN=90 te verkrijgen.
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Hallo satvrienden,
Verdere ontwikkelingen:
Zoals reeds eerder vermeld is de postite van nano82, van zeer belang.
We moeten de nano82 op zoveel mogelijke posities plaatsen. Het doel is dan ook om een mooie 90 1D te krijgen.....
Nano82 geplaatst achter de P4 (01), met het bijvoegen van 90 bytes met de waarde 00, en wederom de zoektocht naar de 90 1D realiseren.
C1 3C 01 BF 5D 10 01 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
3B F7 11 00 01 40 96 70 70 07 0E 6C B6 D6 90 00
--------------------------------------------------
------ CAM -> CARD -------Aantal keer verstuurd: 1
CLASS: C1
INS : 3C
P1 : 01
P2 : BF
LEN : 5D
----- Data v/d Ins = 3C------------------------
3C <--Eco kaart ontvangen
10 01 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
ACK kaart ontvangen-->90 02
Totdat we bij de de volgende INS 3C zijn, zal de kaart nooit een 90 1D antwoorden:
C1 3C 01 BF 63 10 01 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 81 -> 90 1D
------ CAM -> CARD -------Aantal keer verstuurd: 1
CLASS: C1
INS : 3C
P1 : 01
P2 : BF
LEN : 63
----- Data van de Ins = 3C------------------------
3C <--Eco kaart ontvangen
10 01 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 81
ACK kaart ontvangen-->90 1D
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Heb nog wat meer tests gedaan, zoals bv: nano82 1, 2, 3 etc.. postitie ervoor
of erna plaatsen.
Als resultaat krijgen we 90 02, 90 37, m.a.w. varierende 'results'
Conclussie:
Naar mijn mening maakt de Ins 3C, zoals in mijn eerdere post reeds vermeld, gebruik van 92 data.
Deze theorie wordt bevestigd door Novatorx (een van de meesters die zeer intens bezig is betreffende nano82), ziehier zijn bevindingen:
Bron: Novatorx -> top digital.
C1 3C 01 BF 90 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
C1 3C 01 BF 90 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 -> 90 02
Azazel, zoals je ziet bevestigd dit je theorie, we delen de INS 3C met LEN=90 (144 dec) + bijvoegen van de bytes met waarde 00 vanaf P4 tot waar volgens jou nano82 theoretisch moet staan + 90 bytes met waarde 00 om eerder genoemde nano buiten de SSE te krijgen.
Ik zal telkens een byte 00 in de SSE bij voegen en verplaatsen van één byte, links van de 'theoretische' positie van de nano82.
Hiermee kun je ook het aantal bytes in de SSE kunnen zien, die we nog nodig zullen hebben in onze verdere studie.
C1 3C 01 BF 90 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 81 -> 90 1D
C1 3C 01 BF 90 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 73 90 1D
C1 3C 01 BF 90 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 AE 90 1D
C1 3C 01 BF 90 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 20 90 1D
C1 3C 01 BF 90 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 B8 90 1D
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C1 3C 01 BF 90 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 36 90 1D
C1 3C 01 BF 90 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 57 90 1D
C1 3C 01 BF 90 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 9C 90 1D
C1 3C 01 BF 90 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 DB 90 1D
C1 3C 01 BF 90 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 53 90 1D
C1 3C 01 BF 90 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 B4 90 1D
zie volgende post voor vervolg.
-
@fluister,
Je hebt het goed gezien betreffende de waarde PZ-34, dit is een nano.
Ook leuk om te weten is dat de INS waar ze nu gebruik van maken zitten 92 data.
Als we de P3 en P4 (10 01) aftellen, dan blijven er nog 90
bytes over die met de SSE staan.
De positie van nano 82 is hierbij van belang om te weten.
Naar mijn mening zou die op de 7e byte na de P4 moeten staan???
Na deze 'theoretische posisitie' houden we 83 bytes over
(als we de 8 bytes va de MK v/d 'signature' er ook aftellen dan
houden we 75 bytes over).
Tevens om de Len van 5C compleet te maken, waarbij aangeeft Pz=P5 bij de laatste byte van INS 3C.(volgens de 'meesters' moet deze byte LB=Last Byte er als volgt uitzien):
C1 3C 01 BD 5C 10 01 A1 A2 A3 A4 A5 A6 [82] SI GN AT UR E*
Pz-74 Pz-73 Pz-72..Pz-2 Pz-1 Pz=P5=LB
Saludos!
'Azazel miembro del equipo RAIDEN, la resitencia.'
-
Hallo satvrienden,
Ook ik wil niet achterblijven en daarom voor iedereen nog de beste wensen voor het nieuwe jaar!
Dat het jaar 2003 voor iedereen vol geluk en gezondheid mag brengen, en natuurlijk veel satplezier.
En een speciaal gelukkig nieuwjaar voor alle moderators en administrators van sat4all, en dat we nog lang mogen blijven genieten van deze geweldige forum!!!
Saludos!
'Azazel miembro del equipo RAIDEN, la resistencia.'
-
Vervolg.....
C1 3C 01 BF 6E 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 81 -> 90 1D
C1 3C 01 BF 6E 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 0E 81 -> 90 1D
C1 3C 01 BF 6E 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 3D 0E 81 -> 90 1D
C1 3C 01 BF 6E 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 65 3D 0E 81 -> 90 1D
C1 3C 01 BF 6E 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 BD 65 3D 0E 81 -> 90 1D
C1 3C 01 BF 6E 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 22 BD 65 3D 0E 81 -> 90 1D
C1 3C 01 BF 6E 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 92 BD 65 3D 0E 81 -> 90 1D
C1 3C 01 BF 6E 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 29 22 BD 65 3D 0E 81 -> 90 1D
C1 3C 01 BF 6E 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 8B 22 BD 65 3D 0E 81 -> 90 1D
C1 3C 01 BF 6E 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 D4 22 BD 65 3D 0E 81 -> 90 1D
C1 3C 01 BF 6E 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 03 92 BD 65 3D 0E 81 -> 90 1D
C1 3C 01 BF 6E 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 55 92 BD 65 3D 0E 81 -> 90 1D
C1 3C 01 BF 6E 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 87 92 BD 65 3D 0E 81 -> 90 1D
C1 3C 01 BF 6E 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 C1 92 BD 65 3D 0E 81 -> 90 1D
C1 3C 01 BF 6E 3C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 D7 92 BD 65 3D 0E 81 -> 90 1D
By Novatorx..
----------------------------------------------------------------------------
Wat ik hier aan toe wil voegen is de volgende tests die ik heb gedaan:
Ik begin vanaf 00 en van Pz-1
Versturen en zoeken naar respons 90 1D
C1 3C 01 BF 90 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 01 C6
Status: 90 37
C1 3C 01 BF 90 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 02 C6
Status: 90 02
C1 3C 01 BF 90 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 03 C6
Status: 90 02
en zo verder tot het veranderen van de byte byte Pz-1 tot FF.
We zullen dan zien dat voor waarde 99, het repsons van de kaart 90 1D zal zijn!!
C1 3C 01 BF 90 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 99 C6
Status: 90 1D
We bewaren dus deze waarde in de ins, en gaan vervolgens door naar de volgende byte, Pz-2
C1 3C 01 BF 90 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 01 99 C6
Status: 90 37
C1 3C 01 BF 90 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 02 99 C6
Status: 90 37
C1 3C 01 BF 90 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 03 99 C6
Status: 90 37
en zo verder tot verandering van de byte Pz-2, tot FF.
Net als eerder, we bewaren de waarde waardoor we de 90 1D verkrijgen, in dit geval dus de C8
C1 3C 01 BF 90 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 C8 99 C6
Status: 90 1D
Totdat we de byte Pz-33 bereiken, is het alleen mogelijk, als ik het dus goed heb gedaan, om de 90 1D te verkrijgen met een bepaalde waarde in Px.
Vanaf Pz-34, kunnen we zien dat er meer dan een waarde is waardoor we dus die 90 1D verkrijgen.
Dus Pz-34 kan waardes hebben van 35, 4E en 9F, en met elk van deze zal de kaart de 90 1D geven:
C1 3C 01 BF 90 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 35 FD DB D3 FA CE C0 03 05 00 0B 00 F3 A4 4B 00 D3 37 F5 9B 2D 00 A6 07 E7 C4 6A 53 F7 07 00 C8 99 C6
Status: 90 1D
C1 3C 01 BF 90 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 4E FD DB D3 FA CE C0 03 05 00 0B 00 F3 A4 4B 00 D3 37 F5 9B 2D 00 A6 07 E7 C4 6A 53 F7 07 00 C8 99 C6
Status: 90 1D
C1 3C 01 BF 90 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 9F FD DB D3 FA CE C0 03 05 00 0B 00 F3 A4 4B 00 D3 37 F5 9B 2D 00 A6 07 E7 C4 6A 53 F7 07 00 C8 99 C6
Status: 90 1D
Maar nu is mijn vraag???
Als we volgens deze methode verdergaan, wat hebben we dan bereikt en kunnen we nog bereiken???
Deze vraag heb ik ook gesteld op spaanse forums:
Enkele antworden:
- Data Pz-34, is een nano
- Deze data geeft het begin of het einde aan van de SSE!!
- De data Pz tot Pz-33, moeten we die '00' analiseren en er achter zien te komen wat de betekennis is.
Goed, ik weet het nu ook ff niet meer...... ga ff slapen en morgen weer met een frisse kop vrolijk verder....
Saludos!
'Azazel miembro del equipo RAIDEN, la resistencia.'
-
Hallo satvrienden,
Na lange dagen en wat nachten werk en diverse discussies, testen, uitproberen, berekenen, etc. etc. hebben we het volgende gedaan, naar aanleiding van de posts van Kimble.
@Kimble, zou graag je menig willen weten. Kijk er ff aandachtig naar.
We zijn weer een stapje dichterbij, denk ik....
Ideeen en Instructies bedacht door mijn goede vriend novatorx.
De volgende Ins. verstuurd:
C1 3C 01 BD 5C 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
Respons:
10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
ACK kaart ontvangen-->90 02
Wijziging van de nibble (inferieur) van P2 voor F (OK - 0F)
C1 3C 01 BF 5C
10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
ACK kaart ontvangen -->90 02
Wijziging van LEN, verplaatsen wat in theorie nano82 en zijn bytes v/d 'signature'.
C1 3C 01 BF 6E 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
Wat van belang is hier om het vinden van (m.b.v. test70) de goede byte voor de Pz=P5 en een 90 1D te verkrijgen.
Om dit te doen, moeten we de nano82 in positie 9 (na de P4) te zetten, 00 is geplaatst totdat we de nano82 na de laatste byte v/d 'signature' hebben.
Om de 90 bytes te completeren moeten we ook 00 plaatsen na de theoretische positie va de nano 82 tot Pz.
Hierna krijgen we een serie responsen, die we nader aan het onderzoeken zijn.
Ik zal die t.z.t. hier plaatsen.
Saludos!
'Azazel miembro del equipo RAIDEN, la resistencia.'
-
@Euro,
Waarom trap je er toch in??
Tip voor iedereen:
Voordat je zoiets vind en wil downloaden kijk even wat voor files het zijn..
Je kunt duidelijk zien dat het hier om .exe files gaat!!
En verder wat Alvon zegt... hou dat allen a.u.b. in de gaten, als je er niet zeker van bent even pm'tje naar een van de moderators!!
Saludos!!
'Azazel miembro del equipo RAIDEN, la resistencia.'
-
@Digitalsat2002,
Vanaf de introduktie van de V7, ben ik natuurlijk gaan kijken naar keywissels. Wat ik je hierover kan vertellen is dat de waardes checksum van de operationele keys (OK), steeds veranderen bij een actualisering van keys, OC, 0D. Voor zover ik heb kunnen zien is dat de OK 0E niet veranderd is.
Maar het vreemde hieraan is, dat de waardes checksum verschillend zijn bij elke 'gebruiker', tenminste voor zover ik andere logs heb kunnen zien.
Zie hier de waardes van mijn V7 (laatste twee mnd), let wel dat de waardes checksum natuurlijk verzonnen zijn.
Oktober
01: 00 5D = 5C FF FF FF FF FF FF FF FF AA 00 81 - Primaire key 0C
01: 00 0C = 5E FF FF FF FF FF FF FF FF BB 00 81 - ,, ,, 0E
01: 00 1C = 5D FF FF FF FF FF FF FF FF CC 00 81 - ,, ,, 0D
02: 00 13 = FE FF FF FF FF FF FF FF FF DD 00 82 - ,, ,, 0E
03: 00 1A = FE FF FF FF FF FF FF FF FF EE 00 83 - ,, ,, 0E
November
01: 00 0A = 0C FF FF FF FF FF FF FF FF FF 00 81 - Primaire key 0C
01: 00 0C = FE FF FF FF FF FF FF FF FF GG 00 81 - ,, ,, 0E
01: 00 1C = 5D FF FF FF FF FF FF FF FF HH 00 81 - ,, ,, 0D
02: 00 13 = 5C FF FF FF FF FF FF FF FF II 00 82 - ,, ,, 0E
03: 00 1A = 5E FF FF FF FF FF FF FF FF JJ 00 83 - ,, ,, 0E
Hieruit kunnen we opmaken dat er in ieder geval elke maand een keywissel plaatsvind, steeds de 0c op de maand zelf en de volgende de 0D. De 0E is tot op heden nog niet veranderd. Geruchten gaan rond dat dit waarschijnlijk de key is voor de VIP kaarten.
Wanneer men een C1 40 ontvangt (C1 40 01 B1 5C), en dus de kaart actualiseerd is er iets wat nog vreemd is, waarom is het zo dat alle OK hetzelfde zijn voor alle 'gebruikers' maar met verschillende checksum??
In de theorie stuurt men actualisaties voor elk 256 'gebruikers' die dezelfde SA hebben, maar veronderscheiden door de CUSTW, de laatste byte van de PPUA.
Mischien heeft het te maken met de Master Key, die zou naar alle waarschijnlijkheid voor elk kaart verschillend zijn....
Hoop dat het zo een beetje duidelijk is.
Saludos!
'Azazel miembro del equipo RAIDEN, la resitencia.'
-
@Kimble,
dat zou de enige logische verklaring kunnen zijn...
Nu er achter zien te komen hoe men de nieuwe ciclus kan starten??
Wat je ook kan doen en voor mij nu onverklaarbaar is, is het feit dat je met P2 ook leuk kunt spelen en vreemde resultaten ontvang..
We kunnen verschillende status bytes verkrijgen, afhankelijk wat de waarde P2 is.
Een vb.
Ins: C1 3C 01 [color:"red"] BO DA [/color] 90
-------------------------------
Data ins. = 3C
-------------------------------
10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 C6
ACK kaart ontvangen-->90 4A
Ook hier zien we de positie van nano82, en de invloed die heeft op het respons.
C1 3C 01 [color:"red"] DC, DD, DE [/color] 90
10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 C6
ACK kaart ontvangen-->90 34
Dit vind ik erg vreemd....
Het volgende heb ik geprobeerd:
Hier kunnen we zien dat de status bytes en de waarde van P2, onderling niet kloppen van elkaar en om een logische 'lijst' te verkrijgen hier, heel erg moeilijk is (maar niet onmogelijk?)
C1 3C 01 [color:"red"] Ax, Cx, Ex, 2x, 4x, 6x [/color] 90
10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 C6
ACK kaart ontvangen-->90 24 <<< ins not allowed in atr level 3
Naar mijn mening is dit omdat bit 4 en P2 niet actief zijn. -> daarom status 90 24 (not allowed)
Als ik er snel overheen kijk denk ik dat er geen enkele 'oneven' byte, in de superieure nibble P2 aanwezig is.
We proberen het gewoon:
C1 3C 01 [color:"red"] 1x. 3x, 5x, 7x, 9x [/color] 90
10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 C6
ACK kaart ontvangen-->90 35
Het vreemde hieraan is, is dat we duidelijk kunnen zien dat we status 90 35 kunnen verkrijgen door alleen maar bit 4 bij nibble van P2 te activeren.
Zoals je al zei Kimble, er zijn nog genoeg dingen die we diep onder de loep moeten nemen, de kaart reageert zeer verschillend. En om de reeds verkregen status te krijgen die je hier opnoemt, is het dus noodzakelijk een diepgaand studie te doen, op de waarde P2 en P3. Ook nano82 speelt hier een belangrijke rol in.
Maar ja, dat is mijn mening......
Ps. Je laatste PM, geeft ons dus zeker aan dat we toch voorzichtig te werk moeten blijven.......!!
Saludos!
'Azazel miembro del eqipo RAIDEN, la resistencia.'
-
Hallo satvrienden,
ik zou nog terugkomen omtrent de informatie betreffende onbekende ins. die gevonden blijken te zijn door Genne9000 zijn gevonden....
C1B0 & C1B4 (Onbekende instructies)
Ins > C1 B0 00 00 03
Data > AA BB CC
Echo < C1 B0 00 00 03
Ack < B0
Data < AA BB CC
Status < 90 00
[Comando Accepted]
Men kan de "P1", "P2", en "Len" niet veranderen (6B00 y 6700).
Maar het accepteerd wel 4 bytes data met len "03".
Ins > C1 B0 00 00 03
Data > AA BB CC DD
Echo < C1 B0 00 00 03
Ack < B0
Data < AA BB CC DD
Status < 90 00
[Comando Accepted]
Ins > C1 B4 00 00 08
Data > 00 00 00 00 00 00 00 00
Echo < C1 B4 00 00 08
Ack < B4
Data < 00 00 00 00 00 00 00 00
Status < 90 00
[Comando Accepted]
Als men de "P1","P2" veranderd of de waarde van de 8 bytes met data (ST 9028)
V6.0 (Key checksum incorrect)
De ins. B4 had ik wel ooit eerder gezien, maar de B0 nooit eerder gezien...
Na wat meer rondneuzen, zie deze informatie:
Log van BUTXI by Novatorx.
-------------Ontvangen: Onbekende INS.----------------
CLAS: C1
INS : B2
P1 : 00
P2 : 00
LEN : A0
--------------------------------------------
C1 B2 00 00 A0
------------------------DATA-------------------------
84 7F 7F 7F 7F 7F 7F 7F 7F 7F 7F 7F 7F 7F
7F 7F 7F 7F 7F 7F 7F 7F 7F 7F 7F 7F 7F 7F
7F 7F 7F 7F 50 00 C1 B4 00 00 03 B4 00 00
00 50 00 C1 B2 81 00 A0 B2 C3 00 00 00 00
00 00 00 C0 84 7F 7F 7F 7F 7F 7F 7F 7F 7F
7F 7F 7F 7F 7F 7F 7F 7F 7F 7F 7F 7F 7F 50
00 C1 B4 00 00 03 B4 00 00 00 50 00 C1 B2
82 00 A0 B2 C3 00 00 00 00 00 00 00 00 84
7F 7F 7F 7F 7F 7F 7F 7F 7F 7F 7F 7F 7F 7F
7F 7F 7F 7F 7F 7F 7F 7F 50 00 C1 B4 00 00
03 B4 00 00 00 50 00 C1 B2 03 00 A0 B2 C3
00 00 00 00 00 00 90 00
------------------------------------------------------
-------------Ontvangen: Onbekende INS.----------------
CLAS: C1
INS : B4
P1 : 00
P2 : 00
LEN : 03
---------------------- CABECERA ----------------------
C1 B4 00 00 03
------------------------DATA-------------------------
00 00 00 90 00
------------------------------------------------------
------------------------------------------------------
Error: Got 8E Sent 90
-------------Ontvangen: Onbekende INS.----------------
CLAS: C1
INS : B2
P1 : 81
P2 : 00
LEN : A0
---------------------- CABECERA ----------------------
C1 B2 81 00 A0
------------------------DATA-------------------------
C3 00 00 00 00 00 00 00 C0 84 7F 7F 7F 7F
7F 7F 7F 7F 7F 7F 7F 7F 7F 7F 7F 7F 7F 7F
7F 7F 7F 7F 50 00 C1 B4 00 00 03 B4 00 00
00 50 00 C1 B2 82 00 A0 B2 C3 00 00 00 00
00 00 00 00 84 7F 7F 7F 7F 7F 7F 7F 7F 7F
7F 7F 7F 7F 7F 7F 7F 7F 7F 7F 7F 7F 7F 50
00 C1 B4 00 00 03 B4 00 00 00 50 00 C1 B2
03 00 A0 B2 C3 00 00 00 00 00 00 00 00 84
7F 7F 7F 7F 7F 7F 7F 7F 7F 7F 7F 7F 7F 7F
7F 7F 7F 7F 7F 7F 7F 7F 50 00 C1 3C 81 3D
5C 3C 90 81 47 0E 75 7B 54 1B 36 8A D3 D5
7A AC 41 A7 23 3B 90 00
------------------------------------------------------
Volgens de Seca-faq van Roland von Gilead zien we:
2.1 INS 0x02
De werking van deze ins. is onbekend.
C1 04 P1 00 08
P1 specificeerd zich op de provider, P2 is hier niet nodig.
2.2 INS 0x04
Ook hier is het onbekend. Decrypt 8 bytes met data key provider 0x0F, die we terug kunnen vinden op de kaart.
C1 02 P1 0F 08 xx xx xx xx xx xx xx xx
P1 specificeerd de provider, P2 heeft iets te maken met key 0F. 8 * xx = transfered bytes.
We nemen even de rom6 van HA erbij:
; Ins 02 : output encrypted data with ins 04
; Ins 04 : encrypt data with key F
Hier spreken we natuurlijk over de B0, als we die dus versturen naar seca, mogen we een mooie 90 00 ontvangen.
Zodra ik wat meer informatie heb zal ik er op terugkomen, voor nu... weer een leuk speeltje erbij...
Saludos!
'Azazel miembro del equipo RAIDEN, la resistencia.'
-
Hallo satvrienden,
wat vinden jullie hiervan? Kimble, wat denk jij?
Ins > c1 3c 01 bf 90
Data > 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 f6
Status < 90 37
We nemen en zetten de nano 82 op de postite zoals Kimbel aangeeft:
Ins > c1 3c 01 bf 90
Data > 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 f6
Status < 90 37
Wijzigen van de laatste byte F6 voor C6:
Ins > c1 3c 01 bf 90
Data > 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 c6
Status < 90 1d
Na discussies met div. mensen, is het zo dat een vreemde zaak is? Missen we iets hier??
Kimble, alleen maar even zeggen dat het geweldig is wat je hebt gedaan, en kijk even hiernaar en zou het erg waarderen als je je mening hierover geeft, zodat ik... ja je weet wel, wat we over pm besproken hebben.
Saludos!
'Azazel miembro del equipo RAIDEN, la resitencia.'
-
JONGENS JULLIE ZIJN GEWELDIG!!!!
CB, thanks dat je me ze toch nog op wilde sturen.... ondanks al die vele verzoeken die je hebt via PM, bedankt dat je me eruit gepikt hebt! (had de link net gemist).
Ik ga de files meteen hier in Spanje rond strooien op div. forums, hebben we dit jaar hier toch nog een mooie sinterklaas kado gekregen!!!
De hele pakket gaat open, wekelijk alles, incl. TAQUILLAS!!!
CB.. Duizendmaal dank.... Als ik ooit iets terug kan doen.. zeg het maar he..
-
Hallo satvrienden,
@Kimble,
Ik ben wat aan het spelen geweest met wat ins. en het bekijken betreffende de bits die geactiveerd worden.
Om de studie te vervolgen heb ik even het listje van HA er bij gehaald op basis van de rom6:
; Ins 16 : output providers bitmap, pin prot status, flags and table indicators
; C1 16 00 00 08 answer: 00 00 xx xx aa bb cc dd
; xx xx : providers bitmap
; aa : pin protection status (0=inactive 1=active)
; bb : flags
; bit 0 - addressable bit 01 (20.1)
; bit 1 - addressable bit 06 (20.6)
; bit 2 - addressable bit 07 (20.7)
; bit 3 - addressable bit 03 (20.3)
; bit 4 - addressable bit 05 (20.5)
; bit 5 - addressable bit 02 (20.2)
; bit 6 - addressable bit 00 (20.0)
; bit 7 - addressable bit 08 (21.0)
; cc : algo table a indicator
; dd : algo table b indicator
;---------------------------------------------------------------------------
; Ins 48 : set flags 20.2 and 20.5
; C1 48 00 00 01 (data byte, bit 5 and 4)
;---------------------------------------------------------------------------
Hiermee kunnen we wat testen en wat spelen. Belangrijk om te weten is dat met de ins. 30 we wat kunnen spelen met de status van de pin en de varandering.
Heb ergens gelezen dat de waardes van de flags 00, 10, 20 en 30 zouden kunnen zijn.
Middels de ins.48 kunnen we de bits 4 en 5 activeren, en met de 16 kunnen we het terug lezen.
Ik zit nu nog in discussie met wat andere 'collegas' betreffende deze studie, en we gaan de waardes van de P2 en P3 hierin betrekken.
In een volgende fase zal ik de complete studie, die overigens nog niet klaar is, van de waardes P2 en P3, hierop posten en discusieren.
Overigens na wat rondneuzen en vele uren klatsen, heb ik inmiddels wat informatie bijeen gekregen omtrent de onbekende ins.
Ik zal alle informatie in een nieuwe topic starten.
Saludos!
'Azazel miembro del equipo RAIDEN, la resistencia.'
-
Ok Kimble,
Ik ga met je mee... dus als ik je goed begrijp wil je na iedere instructie de status controleren.. Laat me weten of ik iets kan doen..
Bekijk ook even deze twee instructies: C1B0 & C1B4.
Zover bij mij bekend zijn deze geheel nieuwe instructies, heb je deze ooit eerder gezien. De werking van deze zijn nog niet bekend.
Ik spring hiermee wel van het ene naar het andere, maar mischien dat een en ander verband met elkaar zouden kunnen hebben.
Ps. Ik zal zelf ff op zoek gaan naar informatie omtrent deze nieuwe instructies, mischien dat er iemand is die weet wat ze doen..
Saludos!
'Azazel miembro del equipo RAIDEN, la resistencia.'
-
Sinterklaas wie is dat??
-
@Kimble,
Bekijk dit stukje tekst even, naar aanleiding van jou studie en onderzoek.
Bron CANALTOPDIGITAL.
Jcotu.
Ins > c1 3c 01 bf 90
Data > 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 f6
Status < 90 37
Nu nemen we en plaatsen we nano82 op de postitie zoals die door jou (kimble) wordt aangegeven.
Ins > c1 3c 01 bf 90
Data > 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 f6
Status < 90 37
Nu nemen we en veranderen laatste byte F6 voor C6:
Ins > c1 3c 01 bf 90
Data > 10 01 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 c6
Status < 90 1d
Kimble, een vraag aan jou... zou je de hele analise die je hebt gedaan en waardoor je die C6 hebt verkregen kunnen verklaren. Mischien dat de hele analise in het vervolg van de studie niet interessant is maar we moeten toch alles nagaan, vind je niet?
Verder zou er hier een logische verklaring of theorie op kunnen zijn:
C6=11000110
82=10000010
Het verschil tussen beide binaire waardes van 82 en C6 is dat bit 6 en bit 2 geactiveerd worden.
De waarde van F6 zou logischerwijs 11110110 moeten zijn.
Van 10000010 = 82 gaan we over naar 11000110 = C6, om dit te laten werken zou er een bit geactiveerd moeten worden zoals voorgaande analise, daarom die F6.
Ik denk dat we hiermee een goede weg inslaan en zeker wat kunnen bereiken.
Wat denk je er zelf van?
Saludos!
'Azazel miembro del equipo RAIDEN, la resistencia.'
-
Hallo satvrienden,
Dit stukje tekst en onderzoek van Kimble is ZEER GOED GEVONDEN!
Het is een zeer vreemde zaak die we nu moeten uitzoeken en petje af voor Kimble. Ik heb het een en ander besproken en uiteraard getest. Ook heb ik mijn nieuwe 'satcollega's' van CANALTOPDIGITAL, gevraagd om hier eens naar te kijken, en we hebben dit, uiteraard, onder naam van Kimble, gepost op dat forum.
SSE RSA/720 bits.
C1 3C P1 P2 LEN P3 P4 xx xx xx xx xx .... xx xx 82 s1 s2 ... s7 s8 yy yy yy yy ... yy yy P5
xx xx ... xx -> date
82 s1...s8 -> nano 82
yy yy ...yy -> padding
LEN=5C (92 bytes) nano 82.
Ins 3C met LEN 5C
C1 3C 01 BE 5C 10 01
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 -> 90 02
Niet bestaande key (bv key 0F)
C1 3C 01 BF 5C 10 01
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 -> 90 02
90h bytes:
C1 3C 01 BF 90 10 01
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 -> 90 02
C1 3C 01 BF 90 10 01
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 C6 -> 90 1D
SSE 0x82 wijzigen.
C1 3C 01 BF 90 10 01
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 C6 -> 90 1D
C1 3C 01 BF 90 10 01
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 xx 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 C6 -> 90 02
C1 3C 01 BF 90 10 01
82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 xx 82
82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82
82 82 82 82 82 82 82 82 82 82 82 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 C6 -> 90 02
C1 3C 01 BF 90 10 01
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 C6 -> 90 1D
C1 3C 01 BF 90 10 01
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 C6 -> 90 02
Als ik het tot zover heb kunnen simuleren is er sprake van een bug, kijk eens naar de 6C.
DE RSA is wel duidelijk geworden, de techniek die gebruikt is laat duidelijk zien dat we met een SSE RSA/720 bits hebben te maken.
Denk niet dat ik hiermee ver vandaan zit.
Als je om de instructie door de SSE (Secondery Super Encryption) heen gaat (Bypass), dan kan je dit hoofdstuk in principe overslaan en doorgaan met hoofdstuk3.
Onthoud het volgende.
1) De kaart reset bij bepaalde nano's
2) Er zitten 2 tabellen in
3) Er zijn instructies die je misleiden, en dit zou er best een kunnen zijn, of het is een verschrikkelijke bug.
-
Ik vroeg me dus af wat er zou gebeuren als je een INS 3C met LEN 5C (typische) naar de blackcard verstuurd?
Heb de proef op de som genomen, en het volgende is eruitgerold:
C1 3C 01 BE 5C 10 01
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 -> 90 02
En ik ga ff door met testen.... wat gebeurd er als we hetzelfde INS versturen, maar nu naar een niet bestaand key? (bv Key OF)
C1 3C 01 BF 5C 10 01
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 -> 90 02
En dit is het vreemde...!! Als key OF niet zou bestaan zouden we toch een ander respons moeten krijgen?? Iets in de geest van 90 1D???
Nu ga ik het aantal bytes van de INS verhogen tot bv. 90h bytes:
C1 3C 01 BF 90 10 01
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 -> 90 02
Nu opnieuw met een kleine aanpassing:
C1 3C 01 BF 90 10 01
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 C6 -> 90 1D
Kijk!! Nu krijgen we een andere respons, verlaring hiervoor zou kunnen zijn dat de nano82 is gevonden op de verwachte positie, en is het dus logisch om de 90 1D te krijgen --> geen key aanwezig om de 'firm' na te gaan.
Nu komt het!!
Met seca2 weten we inmiddels dat het proces van de 'firm' wordt toegepast bij de superencrypted Ins, en niet bij de 'vrije' Ins zoals dit bij seca1 het geval was, dus:
1 - De gezochte byte als het resultaat van de de-SSE zou moeten zijn 0x82.
C1 3C 01 BF 90 10 01
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 C6 -> 90 1D
C1 3C 01 BF 90 10 01
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 xx 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 C6 -> 90 02
C1 3C 01 BF 90 10 01
82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 xx 82
82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82
82 82 82 82 82 82 82 82 82 82 82 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 C6 -> 90 02
2 - De postitie staat vast, met uitzondering aan het einde.
C1 3C 01 BF 90 10 01
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 C6 -> 90 1D
C1 3C 01 BF 90 10 01
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 82
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 C6 -> 90 02
Zoals we kunnen zien, de funktie van het resultaat van de de-SSE van de laatste 90 bytes, de kaart gaat dan op zoek naar de nano82 bij de
bepaalde positie.
Als men die daar gevonden heeft, dan gaat het proces 'nagaan van de firm'
door; Als men een andere waarde vind dan geeft hij een 90 02, en als men bij het zoeken (aangegeven door de waarde resulterend van P5, gezien de vorige res.) verder gaat dan de aangegeven data 'velden' of buiten de toegelaten 'velden' dan krijgt men een 90 37 / 90 38.
-
De nieuwe INS voor seca2 C1 3C y C1 40) moeten op zijn minst een minimale
lengte hebben van 92 bytes (10 01+90) alhoewel ze ook groter kunnen zijn.
Superencryptie is hierbij verplicht en bovendien zijn de laatste 90 bytes
verbonden aan een onbekende cryptografische die volgens mijn weten ookwel
SSE noemt (Secondary SuperEncrypt) alhoewel men vermoed dat het ook een
encrypt kan zijn tipe RSA/720 bits.
Wat ik denk is middels deze instructie, het eerste wat de kaart doet is
het negeren van de SSE en de instructie op superencrypted laten staan en het
voorzien van een 'firm', wat er dan zoiets zou moeten uitzien:
C1 3C P1 P2 LEN P3 P4 xx xx xx xx xx .... xx xx 82 s1 s2 ... s7 s8 yy yy yy yy ... yy yy P5
xx xx ... xx -> data superencryptie
82 s1...s8 -> nano 82 en firm
yy yy ...yy -> padding
Die 9600 bij jou is niet te verklaren door mij.. Nano's zouden correct moeten zijn??
De kaart leest de waarde van de P5 die de 'nodige' lengte aangeeft en
'knipt' de instructie na de s8 (laatste byte bij de 'firm').
Vervolgens zou het de 'firm' na moeten gaan met de data P3 P4 xx xx ...xx
tot de nano 82 en als deze correct is, dan gaat men over tot het decrypten
van deze data wat de Parameter P2 aangeeft.
Als LEN=5C (92 bytes) we niet de mogelijkheid hebben om te weten te komen
wat de laatste positie is van nano 82, maar als we een INS construeren
met een grotere lengte dan kunnen we enige byte in de laatste 90 varieren,
in de vorm zodat de P5 de kaart laat 'zoeken' naar de nano 82 buiten de
SSE om.
Met de data van superencryptie en de gesitueerde 'firms' buiten de SSE, zou
het mogelijk moeten zijn om een soort 'bypass' te doen op de Secondary
SuperEncrypt.
Mischien is dit weer een vergezochte item van mij, maar het zou moeten kunnen werken...
Wat Jack70 bedoeld is denk ik, om enige data superencrypted met goede 'firms'
te 'breken' (zoals je kunt zien bij de INS 36) om deze vervolgens te versturen
in de vorm van een 38 of een 40, in een vorm zodat de kaart dit accepteerd.
Natuurlijk hebben we op het moment helemaal geen controle op de efecten
volgens dit proces, want we weten niet exact wat we versturen.
-
Hallo satvrienden,
Hier het vervolg van het onderzoek, zodat we nu serieus met het onderwerp verder kunnen gaan, en op verzoek van Duwgati.
Ik zal eerst een korte samenvatting en de belangrijkste punten hier posten, van het topic analise log.
Petitie nummer van providers v/d kaart, bewijst dat seca aanwezig is op
de kaart, status van pin en waardes v/d registers m080.
0004 ... C1 16 00 00 08
00 00 00 0F 00 10 DB DB
90 00
0F = Nummer van providers. 0F(hexadecimaal) = 15(decimaal) = 1111(binair).
Analisatie van de binaire waarde: 1111 >>>> 4 providers aanwezig. SECA + 0064 + 0066 + 0067
00 = Status pin. 00 = Niet aanwezig
10 = Status van de bits 4 y 5 in de registers m080. 10(hexadecimaal) = 16(decimaal) = 10000(binair)
Analiseren van binaire waarde: 10000 >>>> waarde 4.bit = 1 , waarde 5.bit = 0
DB = Indicatie van algoritme tabel A
DB = Indicatie van algoritme tabel B
Petitie indentificatie van seca en providers. P1 geeft de aangevraagde provider aan.
0005 ... C1 12 00 00 18
00 00 53 45 43 41 20 20 20 20 20 20 20 20 20 20 20 20 00 00 00 00 00 00
90 00
00 00 = SECA ID
53 45 43 41 20 20 20 20 20 20 20 20 20 20 20 20 = Tekst ASCII = SECA
00 00 00 00 = PPUA
00 00 = Datum einde abonement = 00.00.1990
0006 ... C1 12 01 00 18
00 64 43 41 4E 41 4C 53 41 54 C9 4C 49 54 45 20 20 20 XX XX XX XX 19 9F
90 00
00 64 = CANALSATÉLITE ID
43 41 4E 41 4C 53 41 54 C9 4C 49 54 45 20 20 20 = Tekst ASCII = CANALSATÉLITE
XX XX XX XX = PPUA
19 9F = Datum einde abonement = 31.12.2002
0007 ... C1 12 02 00 18
00 66 43 41 4E 41 4C 53 41 54 C9 4C 49 54 45 32 20 20 XX XX XX XX 19 9F
90 00
00 66 = CANALSATÉLITE2 ID
43 41 4E 41 4C 53 41 54 C9 4C 49 54 45 32 20 20 = Tekst ASCII = CANALSATÉLITE2
XX XX XX XX = PPUA
19 9F = Datum einde abonement = 31.12.2002
0008 ... C1 12 03 00 18
00 67 43 41 4E 41 4C 53 41 54 C9 4C 49 54 45 33 20 20 XX XX XX XX 19 9F
90 00
00 67 = CANALSATÉLITE3 ID
43 41 4E 41 4C 53 41 54 C9 4C 49 54 45 33 20 20 = Tekst ASCII = CANALSATÉLITE3
XX XX XX XX = PPUA
19 9F = Datum einde abonement = 31.12.2002
**************************************************
****
Petitie register PBM. Hier, de C1 32, geeft de provider waar men de
informatie op aanvraagt (P1)
0009 ... C1 34 00 00 03
00 00 00
90 00
0010 ... C1 32 00 00 20 >>> P1 = 00 = SECA
04 FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF
90 00
04 = Nano 4 met de lengte 0 = Geen data meet te verkrijgen. Geen PBM voor
deze provider
0011 ... C1 34 00 00 03
00 00 00
90 00
0012 ... C1 32 01 00 20 >>> P1 = 01 = CANALSATÉLITE
83 00 00 00 00 00 00 30 86 04 FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF
90 00
83 = Nano 3 met lengte 8 = 8 bytes met data
00 00 00 00 00 00 30 86 = PBM CANALSATÉLITE
04 = Nano 4 met data 0 = Geen data meer aanwezig
0013 ... C1 34 00 00 03
00 00 00
90 00
0014 ... C1 32 02 00 20
83 00 00 00 00 00 00 00 00 04 FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF
90 00
83 = Nano 3 met lengte 8 = 8 bytes met data
00 00 00 00 00 00 00 00 = PBM CANALSATÉLITE2
04 = Nano 4 met lengte 0 = Geen data meer aanwezig
0015 ... C1 34 00 00 03
00 00 00
90 00
0016 ... C1 32 03 00 20
83 00 00 00 00 00 00 00 00 04 FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF
90 00
83 = Nano 3 met lengte 8 = 8 bytes met data
00 00 00 00 00 00 00 00 = PBM CANALSATÉLITE3
04 = Nano 4 met lengte 0 = Geen data meer aanwezig
********************************************************************
Maestro Home Alone zei ons bij de rom6:
; Ins 16 : output providers bitmap, pin prot status, flags and table
indicators
; C1 16 00 00 08 answer: 00 00 xx xx aa bb cc dd
; xx xx : providers bitmap
; aa : pin protection status (0=inactive 1=active)
; bb : flags
; bit 0 - addressable bit 01 (20.1)
; bit 1 - addressable bit 06 (20.6)
; bit 2 - addressable bit 07 (20.7)
; bit 3 - addressable bit 03 (20.3)
; bit 4 - addressable bit 05 (20.5)
; bit 5 - addressable bit 02 (20.2)
; bit 6 - addressable bit 00 (20.0)
; bit 7 - addressable bit 08 (21.0)
; cc : algo table a indicator
; dd : algo table b indicator
;-------------------------------------------------------------------------------
; Ins 48 : set flags 20.2 and 20.5
; C1 48 00 00 01 (data byte, bit 5 and 4)
;-------------------------------------------------------------------------------
Naar aanleiding van beide INS kunnen we een beetje 'spelen' met de 48, we
veranderen in de ram de flag en met de 16 vragen we de register op, maar
opnieuw krijgen we dezelfde meededeling, dat er in de realiteit niets
veranderd op de kaart.
Ook wil ik vermelden dat volgens de INS 30 we kunnen 'spelen' met de status
van de pin en zijn verandering, maar dat zal ik een andere keer doen.
De waardes van de flag kunnen zijn: 00, 10, 20 y 30
****************************************************************************
Middels de INS 48 is het dus mogelijk om de indicatiegever van de tabellen
algoritme te veranderen, maar het effect gebeurd in het RAM geheugen van de kaart, daarom denk ik dat nadat er een reset is geweest de kaart terug gaat naar originele staat...???
Hoe zie jij dit? Zou je dit mischien ook kunnen testen om te kijken wat de resultaten zijn?
Wat je nog verder in de gaten moet houden, volgens de theorie van Home Alone
is:"20.5 5 ppv management (clear=all event transactions allowed) set by ins 48".
20.2 2 eeprom update indication (if set then indicate eeprom update in ins 40)
; set by ins 48
*****************************************************************************
Wat betreft de bug op de nieuwe kaarten, zijn er wel degelijk vooruitgang geboekt, kijk even naar het volgende berichtje:
by jack70
Status 9600 en nieuwe Bug !!!
In de INS 3C en 40, bij de v6.2 betekende, dat de voorbereiding van de nano had gefaald.
quote:
-----------------------------------------
9600 -->ins 0C P2=1 nano 23-90 absentins, ins 38 nano incorrect, ins 3C nano
82 nano problems, ins 3C nano 2C-15 null event
-------------------------------------------
We zullen ditzelfde toepassen op de v7.0.
1) We gebruiken een cimando van de volgende type:
C1 40 0y Dz 6D 10 01 33 44 55 66 77 88 99 00 ss 11 22 33 44
55 66 77 88 C1 C2 C3 C4. .. C90
We varieren nu de bytes Ci (1<=<=90) met als doel om een
9034 te verkrijgen met ss=82 en de 9037 met ss!= 82.
2) Vervolgens nemen we een serie van geldige EMMs en gebruiken dan de
bug 38/36 met als doel om het volgende te verkrijgen:
C1 36 2y P2 14 - > 13 h1 h2 h3 h4 h5 h6 h7 h8 h9 h10 82
j1 j2 j3 j4 j5 j6 j7 j8 9000
Dus h1>=10h en h2=x9h of x1h (waarbij x een nummer is tussen de
0 en F) .
Het kan ook zijn dat h1<=Dfh (nodige conditie, alleen maar bedoeld voor de
gebruikte comando (zie 1), vergroten van de LEN van de comando, zoals volgens
deze condities moet horen.
Voor elke EMMs kunnen we proberen: P2=90h 91h B0h B1h F0h F1h
3) We versturen de comando verkregen onder punt 1, maar met bijvoeging
van de Bytes verkregen onder punt 2.
C1 40 2y P2 6D h1 h2 h3 h4 h5 h6 h7 h8 h9 h10 82 j1 j2 j3
j4 j5 j6 j7 j8 c1 c2. .. c90 - >
-
@Duwgati
Nogmaals sorry voor het feit dat ik het stukje tekst niet in het Nederlands heb gepost. Ik waardeer jullie standpunt, en sta er ook volledig achter.
@Satfreek,
Bedankt voor de vertaling die je voor me hebt gedaan. Ik voel me een beetje schuldig voor het feit dat je door mij in deze situatie bent terechtgekomen, en wil je daarom ook vragen dat we respect moeten hebben voor beslissingen genomen door moderators, en vooral de regels van het board.
Het is mijn fout en zal het ook meteen rechtzetten, en in het vervolg zal ik de moeite nemen om dit soort teksten direct naar het Nederlands te vertalen.
Enne ga vooral door met het plaatsen van berichten op het seca2 forum!
@Allen
Gezien het belang van de samenwerking tussen ons en topdigital, waar zeer grote kenners rondlopen, vind ik het uiterst belangrijk dat dit stukje tekst door iedereen te lezen moet zijn.
X SAT4all:
Ik zou het zeer waarderen als je alles wat ik nu zal zeggen op het sat4all forum wil plaatsen, a.u.b.:
Mijn intentie was nooit om een 'oorlog' te creeren tussen de forums onderling, en ook niet om jullie groep te aanvallen. In tegenstelling zelfs.
Iedereen die me kent, weet dat ik altijd de intentie heb om het gezamelijk delen en bij elkaar brengen van forums en kennis, zo ook als altijd eerlijk proberen te zijn, al doet dit soms pijn, wetende ook dat ik fouten kan maken.
Mijn 'fout' was of is het begin niet begrijpen van de topic gestard door AZAZEL. Eenmaal toen deze mij vertaald werd aangereikt, de rest wat ik heb gezegd in Uw forum, was teveel gezegd.
Ik zou, vanaf hier, heel graag mijn verontschuldigingen willen aanbieden aan alle leden van dit forum en vragen dat vanaf nu we vrienden zouden kunnen zijn, in meerdere kwesties. We zullen ontzettend blij zijn als we gezamelijk alle kennis en studies zouden kunnen uit wisselen met jullie, betreffende alle zaken m.b.t. seca2.
Ik hoop, eerlijk gezegd, dat dit een begin is op een langdurige relatie tussen onze leden van beide forums.
Vriendelijke Groeten
PALMATRON. MODERATOR VAN CANALTOPDIGITAL.
Saludos!
'Azazel miembro del equipo RAIDEN, la resistencia.'
-
Hallo satvrienden,
Met respect voor dit forum en die van topdigital nog even de verontschuldigingen aangeboden door Palmatron. Ik hoop dat hun 'team' in het vervolg een positieve bijdrage kan leveren aan ons en op deze board en hoop op een langdurige samenwerking.
Sorry voor het feit dat het in spaans is, en we zouden het enorm waarderen als iemand het zou kunnen vertalen. Dit is toch een stukje belangrijke tekst van mensn van topdigital en het zal ons allen ten gunste komen.
--------------------------------------------------------------------------
X SAT4all:
Me gustaría que pusieras en tu Foro lo que te voy a decir, por favor:
Mi intención NUNCA fue crear una "guerra" entre Foros ni atacar al vuestro. Muy al contrario. La gente que me conoce, sabe que la intención de PALMATRON es la de hermanar foros y conocimientos, así como la de decir la verdad duela a quien le duela, sabiendo al mismo tiempo reconocer sus fallos.
Mi "fallo" fué o a sido no entender el principio del hilo posteado por AZAZEL. Una vez que me lo han traducido, el resto de lo que he dicho en vuestro foro SOBRA.
Quisiera, desde aquí, pedirle disculpas a todos los miembros de tu Foro y pediros que desde ahora podamos ser amigos en todo los sentidos. Estaremos encantados de poder compartir conocimientos y estudios en todo lo referente al tema de S**A 2.
Espero, sinceramente, que este sea el principio de una larga relación entre nuestros Foros.
Atentamente.
PALMATRON. MODERADOR DE CANALTOPDIGITAL.
__________________
FORO.CANALTOPDIGITAL.COM OS DESEA FELIZ NAVIDAD.
Vervolg onderzoek
in CI, CI+, (soft)cams en smartcards
Geplaatst:
Aan al diegenen met een season2-logger
De season2-logger is een leuk speeltje. Bij zeca1 werkte deze perfect. Ook bij seca2 gaat het wel.
De meeste ins. zijn wel bekend, maar ik denk dat er mischien nog een aantal ontbreken.
Wat je dus zou kunnen doen is op zoveel mogelijk verschillende tijden en kanalen te loggen, en goed uit kijken naar 'vreemde' ins.
Je krijgt dus een veel data binnen, kijk naar de ECM ins.
Voor meer info, kijk even op de pagina van Duwgatie, daar staat uitgebreide informatie betreffende het loggen.
Ik voeg deze antwoord hier op de forum ipv PM (hoop dat je het niet erg vind), zodat er meerderen met een season kunnen gaan spelen, en een bijdrage kunnen leveren naar het vervolg van de studie.
Saludos!
'Azazel miembro del equipo RAIDEN, la resistencia.'